SCIN131 131- mole of C21(H15O)2 contains

Question 1 of 124.0 Points1 mole of C21(H15O)2 contains: A.15 moles of hydrogen. B.1 mole of oxygen. C.42 moles of carbon. D.30 moles of hydrogen.Question 2 of 124.0 PointsWhich of these compounds contains the highest percentage of phosphorus by mass? C5H11N2O2P, C7H16FO2P, or C4H10FO2P A.C5H11N2O2P B.C7H16FO2P C.C4H10FO2P D.All of these compounds have the same percentage of phosphorous.Question 3 of 124.0 PointsWhat kind of reaction is represented by the equation below?C3H8(g) + 5 O2(g) —–> 3 CO2(g) + 4 H2O(g) A.precipitation B.acid-base neutralization C.no reaction will occur D.oxidation-reductionQuestion 4 of 124.0 PointsWhen you are balancing the reaction __NO2 + __H2O + __O2 → __HNO3 , what number goes in front of O2? A.5 B.2 C.3 D.4 E.1Question 5 of 124.0 PointsWhich of the following is an indication that a chemical reaction has taken place? A.gas formation B.color change C.solid (precipitate) formation D.All of the above are evidence of a chemical reaction.Question 6 of 124.0 PointsWhen carbon is completely combusted in oxygen what gas is produced? A.chlorine B.nitrogen C.hydrogen D.carbon dioxide E.oxygenQuestion 7 of 124.0 PointsGiven the following equation:2 Ag + H2S –> Ag2S + H2If 2.00 g of H2S reacts with 4.00 g Ag, what would be the limiting reactant? A.silver B.silver sulfide C.hydrogen sulfide D.hydrogen E.There is no limiting reactant in this caseQuestion 8 of 124.0 PointsGiven the following equation:4 NH3 + 5 O2→ 4 NO + 6 H2OIf 4.00 mol of water are formed, how many moles of NO will be formed? A.7.72 mol. B.2.66 mol. C.5.14 mol. D.4.58 mol.Question 9 of 124.0 PointsWhich of the following statements is NOT true? A.percent yield = (actual yield / theoretical yield) × 100% B.The theoretical yield is the amount of product that can be made based on the amount of limiting reactant. C.The limiting reactant is completely consumed in a chemical reaction. D.The actual yield is the amount of product actually produced by a chemical reaction. E.All of the above are true statements.Question 10 of 124.0 PointsIf the theoretical yield is 100.0 grams of product, and the percent yield is 75.0%, what is the actual yield? A.150. B.75.0 C.100.0 D.3,750 E.none of the aboveQuestion 11 of 125.0 PointsAssume you take a sample of 13.6 g Al and oxidize it (in an excess of O2) to produce 12.07 g of Al2O3. Calculate the percent yield of Al2O3. Reaction: 4 Al + 3 O2 → 2 Al2O3. You must show all work to receive credit. All numbers immediately following elemental symbols are subscripts.Question 12 of 125.0 PointsGiven the following equation: 4 Sb + 3 O2 –>2 Sb2O3If you are given 9.20 g Sb, how many grams of Sb2O3 could you theoretically produce?You must show all work clearly and in detail to receive credit. All numbers immediately following elemental symbols should be understood as subscripts.