##P(O,O) = 2/12 xx 1/11 = 1/66##
For probability questions, think of each event happening separately, it makes the maths easier to understand. For example, in this question, do not think of the two boys taking a fruit at the same time – that makes the maths complicated
.
Let Daniel take a fruit first, then Sean can take a fruit. There are two parts to consider.
##Probability = “number of desirable outcomes”/”total number of possible outcomes”##
For Daniel: there are 12 different pieces of fruit in the bowl, he just takes one without choosing a specific fruit. (random)
The chance that Daniel takes an orange is ##2/12##
Of the 12 pieces of fruit. 2 are oranges.
Now Sean: the numbers of fruit in the bowl have changed. There are now only 11 pieces of fruit in the bowl, and only 1 is an orange.
The chance that Sean takes an orange is ##1/11##
The probability that BOTH take an orange is:
##P(O) xx P(O) = 2/12 xx 1/11 = 1/66##
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