STAT 3001 Week 4 Project Assignment

Week 4 Project – STAT 3001

Student Name:
Date:

Instructions: To complete this project, you will need the
following materials:
·
STAT DISK User Manual (found in
the classroom in Doc Sharing)
·
Access to the internet to
download the Stat Disk program.

Part
I. Analyze Data

Instructions

Answers

1.
Open the filePassive and Active Smoke using menu
optionDatasetsand thenElementary
Stats, 11th Edition.
This file contains some information on the continine levels in
smokers, nonsmokers exposed to smoke (ETS), and nonsmokers not exposed to
smoke (No ETS). How many
observations are there in this file?

There are 40 samples
with 3 different observations made on each sample for a total of 120
different observations.

2.
What would you expect to find
relative to the continine level in the groups?

The NOETS group lists
the cotinine levels for subjects who are nonsmokers and have no exposure to
environmental tobacco
smoke at home or work.

The ETS group lists
cotinine levels for subjects who are nonsmokers exposed to tobacco smoke at
home or work.

The SMOKERS group lists
cotinine levels for subjects who report tobacco use.
Serum cotinine is a
metabolite of nicotine, meaning that cotinine is produced when nicotine is
absorbed by the body. Higher levels of
cotinine correspond to higher levels of exposure to smoke that contains
nicotine.

Part
II. Descriptive Statistics

3-6 Generate
descriptive statistics for No ETS, Smokers and ETS groups and complete the
following table. Round mean and
standard deviation to 3 decimal places.

Variable

Sample
Mean

Sample
Standard Deviation

Sample Size

No ETS

16.35

62.534

40

Smokers

172.475

119.498

40

ETS

60.575

138.084

40

7. Did you get
the results you expected here? Explain
why.

8. Which of the
three groups experienced the MOST variation? How do you know?

ETS – the variable
in stat disk is the highest at 19067.17

Part
III. Confidence Intervals

9. Generate a 90%
interval for the mean of the No ETS group. Paste your results here.

Margin of error, E =
16.65918

90% Confident the
population mean is within the range:
-0.3091758 < mean <33.00918 10. Generate a 90% interval for the mean of the Smoker group. Paste your results here. Margin of error, E = 31.83449 90% Confident the population mean is within the range: 140.6405 < mean <204.3095 11. Generate a 90% interval for the mean of the ETS group. Paste your results here Margin of error, E = 36.78584 90% Confident the population mean is within the range: 23.78916 < mean <97.36084 12. Create a graph below by illustrating all three confidence intervals on one graph using the tools in your word processor (example below). Stat Disk cannot do this for you.Create yourgraph and turn the font red. For this process, I just used the dashes and wrote a scale below the axes. Here is an example, but it is not based on the data you are analyzing: Case 1 14---------------------42 Case 2 35-------------------------70 ________________________________________ 0 20 40 60 Your Solution: 13. Based on the confidence intervals shown above, what conclusion can you draw about whether the exposure to smoke leads to higher continine levels? Why? Yes the exposure to smoke leads to higher continine levels. Due to the fact that ETS range 23.78916 < mean <97.36084 and No ETS range -0.3091758 < mean <33.00918 Part IV. Hypothesis Testing 14. Your researcher’s claim is that the continine level for the ETS group is not equal to zero. Compose a hypothesis test with a level of significance of .05 to test your claim. Step 1. Determine parameter of interest and compose null and alternative hypotheses. Step 2. Determine the sample mean, sample standard deviation, and sample size. [Hint: You recorded these previously in Part II, #3-6] Step 3. Determine the likelihood that the population mean is actually not equal to 0 by completing aHypothesis Test: One Mean in STAT DISK. Use significance of0.05. Remember to change the pulldown option in Stat Disk to agree with the alternate hypothesis. Paste your results here. Step 4. State your conclusion.Your conclusion statement should include the p-value and level of significance to phrase your conclusion. 15. For your second hypothesis test, your researcher’s claim is that the continine level in the NO ETS group is greater than zero. Perform a hypothesis test using a significance level of .01 to test your claim. Step 1. Determine parameter of interest and compose null and alternative hypotheses. Step 2. Determine the sample mean, sample standard deviation, and sample size. [Hint: You recorded these previously in Part II, #3-6] Step 3. Determine the likelihood that the population mean is actually greater than 0 by completing aHypothesis Test: One Mean in STAT DISK. Use significance of0.01. Remember to change the pulldown option in Stat Disk to agree with the alternate hypothesis. Paste results here. Step 4. State your conclusion.Your conclusion statement should include the p-value and level of significance to phrase your conclusion. 16. Answer the following questions based on the above hypothesis test. a. What is the p-value for the hypothesis test in #15 and what does it represent? (Look at page 383 in the text) b. Given that your data, hypotheses, and p-value do not change,what would need to be different in order for you to REJECT the null hypothesis? (What do you compare to make your rejection decision?) Submit your final draft of your Word file by going to Week 4, Project, and follow the directions under Week 4 Assignment 2. Please use the naming convention "WK4Assgn2+first initial+last name" as the Submission Title.